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Let f : R → R be a function defined by f(x) = Min {x + 1, |x| + 1}. Then which of the following is true ?
 [AIEEE 2007]
  • a)
    f(x) ≥ 1 for al l x ∈ R
  • b)
    f(x) i s not differentiable at x = 1
  • c)
    f(x) is differentiable everywhere
  • d)
    f(x) i s not differentiable at x = 0
Correct answer is option 'C'. Can you explain this answer?
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Let f : R → R be a function defined by f(x) = Min {x + 1, |x| + ...
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Let f : R → R be a function defined by f(x) = Min {x + 1, |x| + ...
It is clear from the figure that f(x) is differentiable everywhere.
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Let f : R → R be a function defined by f(x) = Min {x + 1, |x| + 1}. Then which of the following is true ?[AIEEE 2007]a)f(x) ≥ 1 for al l x ∈ Rb)f(x) i s not differentiable at x = 1c)f(x) is differentiable everywhered)f(x) i s not differentiable at x = 0Correct answer is option 'C'. Can you explain this answer?
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Let f : R → R be a function defined by f(x) = Min {x + 1, |x| + 1}. Then which of the following is true ?[AIEEE 2007]a)f(x) ≥ 1 for al l x ∈ Rb)f(x) i s not differentiable at x = 1c)f(x) is differentiable everywhered)f(x) i s not differentiable at x = 0Correct answer is option 'C'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about Let f : R → R be a function defined by f(x) = Min {x + 1, |x| + 1}. Then which of the following is true ?[AIEEE 2007]a)f(x) ≥ 1 for al l x ∈ Rb)f(x) i s not differentiable at x = 1c)f(x) is differentiable everywhered)f(x) i s not differentiable at x = 0Correct answer is option 'C'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Let f : R → R be a function defined by f(x) = Min {x + 1, |x| + 1}. Then which of the following is true ?[AIEEE 2007]a)f(x) ≥ 1 for al l x ∈ Rb)f(x) i s not differentiable at x = 1c)f(x) is differentiable everywhered)f(x) i s not differentiable at x = 0Correct answer is option 'C'. Can you explain this answer?.
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